js用最简单的方法实现2个数组的交叉一对一合并

let data1 = {“name”: ‘小米’}, {“name”: ‘小红’}, {“name”: ‘

let data1 = [{"name": '小米'}, {"name": '小红'}, {"name": '小花'}, {"name": '小明'}];
let data2 = [
  {"school": "清北", "type": "本科"}, 
  {"school": "浙大", "type": "研究生"}, 
  {"school": "复旦", "type": "大专"}, 
  {"school": "剑桥", "type": "硕士"}
];

let result = data2.map(z=>data1.map(x=>({...x, ...z}))).flat()
console.log('输出结果：',result);
[
    {
        "name": "小米",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小红",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小花",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小明",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小米",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小红",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小花",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小明",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小米",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小红",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小花",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小明",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小米",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小红",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小花",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小明",
        "school": "剑桥",
        "type": "硕士"
    }
]

相关文章